WebMar 29, 2024 · Transcript. Example 4, In an A.P. if mth term is n and the nth term is m, where m n, find the pth term. We know that an = a + (n 1) d i.e. nth term = a + (n 1) d Thus, mth term = am = a + (m 1) d It is given that mth term is n a + (m 1) d = n Also, it is given that nth term is m a + (n 1) d = m First we find common difference, Subtracting (2) from (1) [a + (m 1) d] … WebDec 5, 2024 · If the (m+n)th term of a gp is p and (m-n)th terma is q, show that mth term and nth term are √pq and p (q/p)^m/2n See answers Advertisement kvnmurty Let the …
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WebOct 10, 2024 · asked Oct 10, 2024 in Mathematics by AnjaliVarma (29.6k points) If the (m+1)th, (n+1)th and (r+1)th terms of an AP are in GP and m, n and r are in HP, then the value of the ratio of the common difference to the first term of the AP is (a) 2/n (b) - (2/n) (c) - (n/2) (d) n/2 jee jee mains 1 Answer +1 vote answered Oct 10, 2024 by Ria (55.2k points) WebLet the first term be a and the common ratio be r. Then, the m th term is a r m − 1 and the n th term is a r n − 1, so we get a r m − 1 = n, a r n − 1 = m. We seek the ( m + n) th term, which is a r m + n − 1. Dividing the two equations, we get r m − n = n m r m + n = n m ⋅ r 2 n r m + n − 1 = n r 2 n − 1 m. cincinnati west soccer club logo
Geometric Progression (GP) - Formulas, n^th Term, Sum
WebMar 30, 2024 · Ex 9.3, 23 If the first and the nth term of a G.P. are a and b, respectively, and if P is the product of n terms, prove that P2 = (ab)n. Let a be the first term of G.P & r be the common ratio of G.P Given, first term of G.P = a We know that nth term of G.P = … WebJul 30, 2024 · If (p+q)th and (p-q)th terms of a G.P. are m and n respectively, then write its pth term. asked Jul 26, 2024 in Geometric Progressions by Haifa ( 52.5k points) geometric progressions WebThe p+q term of a GP is m and its p-q term is n show that its p term=√mn. Solution A = a.r ^ (p+q-1) B = a.r^ (p-q-1) pth term = ar^ (p-1) If you multiply A and B terms you get AB = a^2 … cincinnati westside panthers basketball